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Prove this “32-bit system can address a maximum of 4 GB”

1.40K viewsG12-05. AL ICT Operating System
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Prove this “32-bit system can address a maximum of 4 GB

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In a 32-bit system, the term “32-bit” refers to the size of the memory addresses that the system uses to access and reference different locations in its memory. Each memory address in a 32-bit system is represented by 32 binary digits (bits). The number of bits in an address determines the total addressable memory space of the system.

To understand why a 32-bit system can address a maximum of 4 GB (gigabytes) of memory, we need to examine how binary numbers and memory addressing work.

In binary representation, each bit can have two possible states: 0 or 1. A single bit can represent 2 different values (2·1). For example:

  • 0 (binary: 0) and 1 (binary: 1)

Similarly, with 2 bits, we can represent 2·2 = 4 different values:

  • 00 (binary: 0)
  • 01 (binary: 1)
  • 10 (binary: 2)
  • 11 (binary: 3)

Extending this pattern, with 3 bits, we can represent 2·3 = 8 different values, and with 4 bits, we can represent 2·4 = 16 different values, and so on.

Now, in a 32-bit system, there are 32 bits in each memory address. So, the total number of unique addresses that can be represented in this system is 2·32.

Let’s calculate that: 2·32 = 4,294,967,296

The value 4,294,967,296 represents the total number of unique memory addresses that can be used in a 32-bit system. Each address points to a single byte of memory. Since 1 gigabyte (GB) is equal to 1,073,741,824 bytes, we can convert the number of addresses into gigabytes:

4,294,967,296 bytes ÷ 1,073,741,824 bytes per GB ≈ 4 GB

Therefore, a 32-bit system can address a maximum of approximately 4 GB of memory. This is why 32-bit operating systems are limited in their ability to access and utilize memory beyond this 4 GB limit. To address more memory, one would need to move to a 64-bit system, which uses 64-bit memory addresses and can access significantly larger amounts of memory

 

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